JEE Main 202126 Feb, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002Let f(x) be a differentiable function at x = a with f'(a) = 2 and f(a) = 4. Then limx→axf(a)−af(x)x−a\mathop {\lim }\limits_{x \to a} {{xf(a) - af(x)} \over {x - a}}x→alimx−axf(a)−af(x) equals :AOption A. 4 −-− 2aBOption B. 2a + 4COption C. a + 4DOption D. 2a −-− 4CheckSkip · show solution