Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x R. If f(x) attains maximum value at α and g(x) attains minimum value at β, then lim x → -α β ((x - 1)(x² - 5x + 6))/(x² - 6x + 8) is equal to:

Limit, Continuity and Differentiability: JEE Main 2019 Mathematics question

JEE Main 2019 · 12 Apr, Evening shift · Q4231

JEE Main 201912 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x

\in

R. If f(x) attains maximum value at

\alpha

and g(x) attains minimum value at

\beta

, then

\mathop {\lim }\limits_{x \to -\alpha \beta } {{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)} \over {{x^2} - 6x + 8}}

is equal to :