JEE Main 202230 Jun, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002Let f(x)=4x3−11x2+8x−5, x∈Rf(x) = 4{x^3} - 11{x^2} + 8x - 5,\,x \in Rf(x)=4x3−11x2+8x−5,x∈R. Then f :AOption A. has a local minina at x=12x = {1 \over 2}x=21BOption B. has a local minima at x=34x = {3 \over 4}x=43COption C. is increasing in (12,34)\left( {{1 \over 2},{3 \over 4}} \right)(21,43)DOption D. is decreasing in (12,43)\left( {{1 \over 2},{4 \over 3}} \right)(21,34)CheckSkip · show solution
