JEE Main 20178 Apr, Morning shiftMathematicsMediumSets, Relations and Functions168× since 2002Let f(x) = 2¹⁰.x + 1 and g(x)=3¹⁰.x −-− 1. If (fog) (x) = x, then x is equal to :AOption A. 310−1310−2−10{{{3^{10}} - 1} \over {{3^{10}} - {2^{ - 10}}}}310−2−10310−1BOption B. 210−1210−3−10{{{2^{10}} - 1} \over {{2^{10}} - {3^{ - 10}}}}210−3−10210−1COption C. 1−3−10210−3−10{{1 - {3^{ - 10}}} \over {{2^{10}} - {3^{ - 10}}}}210−3−101−3−10DOption D. 1−2−10310−2−10{{1 - {2^{ - 10}}} \over {{3^{10}} - {2^{ - 10}}}}310−2−101−2−10CheckSkip · show solution
