JEE Main 202224 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002Let f(θ)=sinθ+∫−π/2π/2(sinθ+tcosθ)f(t)dtf(\theta ) = \sin \theta + \int\limits_{ - \pi /2}^{\pi /2} {(\sin \theta + t\cos \theta )f(t)dt}f(θ)=sinθ+−π/2∫π/2(sinθ+tcosθ)f(t)dt. Then the value of ∣∫0π/2f(θ)dθ∣\left| {\int_0^{\pi /2} {f(\theta )d\theta } } \right|∫0π/2f(θ)dθ is _____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution