Let f: S → S where S = (0, ∞) be a twice differentiable function such that f(x + 1) = xf(x). If g: S → R be defined as g(x) = log e f(x), then the value of |g''(5) - g''(1)| is equal to:

Limit, Continuity and Differentiability: JEE Main 2021 Mathematics question

JEE Main 2021 · 16 Mar, Evening shift · Q4201

JEE Main 202116 Mar, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let f : S

\to

S where S = (0,

\infty

) be a twice differentiable function such that f(x + 1) = xf(x). If g : S

\to

R be defined as g(x) = log_e f(x), then the value of |g''(5)

-

g''(1)| is equal to :