JEE Main 202127 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f : R →\to→ R be a function such that f(2) = 4 and f'(2) = 1. Then, the value of limx→2x2f(2)−4f(x)x−2\mathop {\lim }\limits_{x \to 2} {{{x^2}f(2) - 4f(x)} \over {x - 2}}x→2limx−2x2f(2)−4f(x) is equal to :AOption A. 4BOption B. 8COption C. 16DOption D. 12CheckSkip · show solution