Let f: R → R be a continuously differentiable function such that f(2) = 6 and f'(2) = 1/48. If ∫₆^(f(x)) 4t³ dt = (x - 2)g(x), then lim x → 2 g(x) is equal to:

Integral Calculus: JEE Main 2019 Mathematics question

JEE Main 2019 · 12 Apr, Morning shift · Q3305

JEE Main 201912 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

Let f : R

\to

R be a continuously differentiable function such that f(2) = 6 and f'(2) =

{1 \over {48}}

. If

\int\limits_6^{f\left( x \right)} {4{t^3}} dt

= (x - 2)g(x), then

\mathop {\lim }\limits_{x \to 2} g\left( x \right)

is equal to :

JEE Main 2019 Integral Calculus Question with Solution (12 Apr Morning shift, Q3305) | JEE Arc