JEE Main 20211 Sep, Evening shiftMathematicsMediumIntegral Calculus369× since 2002Let f : R →\to→ R be a continuous function. Then limx→π4π4∫2sec2xf(x) dxx2−π216\mathop {\lim }\limits_{x \to {\pi \over 4}} {{{\pi \over 4}\int\limits_2^{{{\sec }^2}x} {f(x)\,dx} } \over {{x^2} - {{{\pi ^2}} \over {16}}}}x→4πlimx2−16π24π2∫sec2xf(x)dx is equal to :AOption A. f (2)BOption B. 2f (2)COption C. 2f (2)\left( {\sqrt 2 } \right)(2)DOption D. 4f (2)CheckSkip · show solution
