JEE Main 2009Annual, Paper 1MathematicsMediumSets, Relations and Functions168× since 2002Let f(x)=(x+1)2−1,x≥−1f\left( x \right) = {\left( {x + 1} \right)^2} - 1,x \ge - 1f(x)=(x+1)2−1,x≥−1 Statement - 1 : The set {x:f(x)=f−1(x)}={0,−1}\left\{ {x:f\left( x \right) = {f^{ - 1}}\left( x \right)} \right\} = \left\{ {0, - 1} \right\}{x:f(x)=f−1(x)}={0,−1}. Statement - 2 : fff is a bijection.AOption A. Statement - 1 is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - 1BOption B. Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1COption C. Statement - 1 is true, Statement - 2 is falseDOption D. Statement - 1 is false, Statement - 2 is trueCheckSkip · show solution
