JEE Main 201910 Jan, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f(x)={max{∣x∣,x2}∣x∣≤28−2∣x∣2<∣x∣≤4f\left( x \right) = \left\{ {\matrix{ {\max \left\{ {\left| x \right|,{x^2}} \right\}} & {\left| x \right| \le 2} \cr {8 - 2\left| x \right|} & {2 < \left| x \right| \le 4} \cr } } \right.f(x)={max{∣x∣,x2}8−2∣x∣∣x∣≤22<∣x∣≤4 Let S be the set of points in the interval (– 4, 4) at which f is not differentiable. Then SAOption A. equals {−2,−1,1,2}\left\{ { - 2, - 1,1,2} \right\}{−2,−1,1,2}BOption B. equals {−2,−1,0,1,2}\left\{ { - 2, - 1,0,1,2} \right\}{−2,−1,0,1,2}COption C. equals {−2,2}\left\{ { - 2,2} \right\}{−2,2}DOption D. is an empty setCheckSkip · show solution
