JEE Main 20204 Sep, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f:(0,∞)→(0,∞)f:\left( {0,\infty } \right) \to \left( {0,\infty } \right)f:(0,∞)→(0,∞) be a differentiable function such that f(1) = e and limt→xt2f2(x)−x2f2(t)t−x=0\mathop {\lim }\limits_{t \to x} {{{t^2}{f^2}(x) - {x^2}{f^2}(t)} \over {t - x}} = 0t→xlimt−xt2f2(x)−x2f2(t)=0. If f(x) = 1, then x is equal to :AOption A. 1e{1 \over e}e1BOption B. eCOption C. 12e{1 \over 2e}2e1DOption D. 2eCheckSkip · show solution