JEE Main 202126 Feb, Evening shiftMathematicsHardMathematical Reasoning115× since 2008Let F₁(A, B, C) = (A ∧\wedge∧ ∼\sim∼ B) ∨\vee∨ [∼\sim∼C ∧\wedge∧ (A ∨\vee∨ B)] ∨\vee∨ ∼\sim∼ A and F₂(A, B) = (A ∨\vee∨ B) ∨\vee∨ (B →\to→ ∼\sim∼A) be two logical expressions. Then :AOption A. Both F₁ and F₂ are not tautologiesBOption B. F₁ and F₂ both are tautologiesCOption C. F₁ is not a tautology but F₂ is a tautologyDOption D. F₁ is a tautology but F₂ is not a tautologyCheckSkip · show solution
