JEE Main 201815 Apr, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002Let f : A →\to→ B be a function defined as f(x) = x−1x−2,{{x - 1} \over {x - 2}},x−2x−1, Where A = R −-− {2} and B = R −-− {1}. Then f is :AOption A. invertible and f−1(y)={f^{ - 1}}(y) =f−1(y)= 3y−1y−1{{3y - 1} \over {y - 1}}y−13y−1BOption B. invertible and f−1(y)=2y−1y−1{f^{ - 1}}\left( y \right) = {{2y - 1} \over {y - 1}}f−1(y)=y−12y−1COption C. invertible and f−1(y)=2y+1y−1{f^{ - 1}}\left( y \right) = {{2y + 1} \over {y - 1}}f−1(y)=y−12y+1DOption D. not invertibleCheckSkip · show solution
