Let f: [ - 3, 1] → R be given as f(x) = \ min (x + 6),x² - 3 ≤ x ≤ 0 max x,x², 0 ≤ x ≤ 1.. If the area bounded by y = f(x) and x-axis is A, then the value of 6A is equal to _ _ _ _ _ _.

Integral Calculus: JEE Main 2021 Mathematics question

JEE Main 2021 · 17 Mar, Evening shift · Q30

JEE Main 202117 Mar, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

Let f : [

-

3, 1]

\to

R be given as

f(x) = \left\{ \matrix{ \min \,\{ (x + 6),{x^2}\}, - 3 \le x \le 0 \hfill \cr \max \,\{ \sqrt x ,{x^2}\} ,\,0 \le x \le 1. \hfill \cr} \right.

If the area bounded by y = f(x) and x-axis is A, then the value of 6A is equal to ___________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Integral Calculus Question with Answer (17 Mar Evening shift, Q30) | JEE Arc