Let f: (- 1, 1) → R be a function defined by f(x) = max - | x |, - √(1 - x²) \. If K be the set of all points at which f is not differentiable, then K has exactly -

Limit, Continuity and Differentiability: JEE Main 2019 Mathematics question

JEE Main 2019 · 10 Jan, Evening shift · Q4190

JEE Main 201910 Jan, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let f : (

-

1, 1)

\to

R be a function defined by f(x) = max

\left\{ { - \left| x \right|, - \sqrt {1 - {x^2}} } \right\}.

If K be the set of all points at which f is not differentiable, then K has exactly -