JEE Main 202230 Jun, Morning shiftMathematicsMediumDifferential Equations163× since 2002Let dydx=ax−by+abx+cy+a, a,b,c∈R{{dy} \over {dx}} = {{ax - by + a} \over {bx + cy + a}},\,a,b,c \in Rdxdy=bx+cy+aax−by+a,a,b,c∈R, represents a circle with center (α\alphaα, β\betaβ). Then, α\alphaα + 2β\betaβ is equal to :AOption A. −-−1BOption B. 0COption C. 1DOption D. 2CheckSkip · show solution
