Let C₁ be the curve obtained by the solution of differential equation 2xydy/dx = y² - x²,x > 0. Let the curve C₂ be the solution of 2xy/(x² - y²) = dy/dx. If both the curves pass through (1, 1), then the area enclosed by the curves C₁ and C₂ is equal to:

Differential Equations: JEE Main 2021 Mathematics question

JEE Main 2021 · 16 Mar, Evening shift · Q3607

JEE Main 202116 Mar, Evening shiftMathematicsMediumDifferential Equations163× since 2002

Let C₁ be the curve obtained by the solution of differential equation

2xy{{dy} \over {dx}} = {y^2} - {x^2},x > 0

. Let the curve C₂ be the solution of

{{2xy} \over {{x^2} - {y^2}}} = {{dy} \over {dx}}

. If both the curves pass through (1, 1), then the area enclosed by the curves C₁ and C₂ is equal to :

JEE Main 2021 · 16 Mar, Evening shift · Q3607

JEE Main 202116 Mar, Evening shiftMathematicsMediumDifferential Equations163× since 2002

Let C₁ be the curve obtained by the solution of differential equation

2xy{{dy} \over {dx}} = {y^2} - {x^2},x > 0

. Let the curve C₂ be the solution of

{{2xy} \over {{x^2} - {y^2}}} = {{dy} \over {dx}}

. If both the curves pass through (1, 1), then the area enclosed by the curves C₁ and C₂ is equal to :