JEE Main 202331 Jan, Evening shiftMathematicsHardDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (3y2−5x2)y dx+2x(x2−y2)dy=0\left(3 y^{2}-5 x^{2}\right) y \mathrm{~d} x+2 x\left(x^{2}-y^{2}\right) \mathrm{d} y=0(3y2−5x2)y dx+2x(x2−y2)dy=0 such that y(1)=1y(1)=1y(1)=1. Then ∣(y(2))3−12y(2)∣\left|(y(2))^{3}-12 y(2)\right|(y(2))3−12y(2) is equal to :AOption A. 64BOption B. 16216 \sqrt{2}162COption C. 32DOption D. 32232 \sqrt{2}322CheckSkip · show solution
