Let y(x) be the solution of the differential equation (x log x)dy/dx + y = 2x log x,(x ≥ 1). Then y(e) is equal to:

Differential Equations: JEE Main 2015 Mathematics question

JEE Main 2015 · Session, Shift 1 · Q3508

JEE Main 2015Session, Shift 1MathematicsEasyDifferential Equations163× since 2002

Let

y(x)

be the solution of the differential equation

\left( {x\,\log x} \right){{dy} \over {dx}} + y = 2x\,\log x,\left( {x \ge 1} \right).

Then

y(e)

is equal to :

JEE Main 2015 · Session, Shift 1 · Q3508

JEE Main 2015Session, Shift 1MathematicsEasyDifferential Equations163× since 2002

Let

y(x)

be the solution of the differential equation

\left( {x\,\log x} \right){{dy} \over {dx}} + y = 2x\,\log x,\left( {x \ge 1} \right).

Then

y(e)

is equal to :