JEE Main 20244 Apr, Evening shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2+4)2dy+(2x3y+8xy−2)dx=0(x^2+4)^2 d y+(2 x^3 y+8 x y-2) d x=0(x2+4)2dy+(2x3y+8xy−2)dx=0. If y(0)=0y(0)=0y(0)=0, then y(2)y(2)y(2) is equal toAOption A. 2π2 \pi2πBOption B. π8\frac{\pi}{8}8πCOption C. π16\frac{\pi}{16}16πDOption D. π32\frac{\pi}{32}32πCheckSkip · show solution
