JEE Main 202628 Jan, Evening shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation xdydx−y=x2cotxx\frac{dy}{dx} - y = x^2\cot xxdxdy−y=x2cotx, x∈(0,π)x \in (0, \pi)x∈(0,π). If y(π2)=π2y\left(\frac{\pi}{2}\right) = \frac{\pi}{2}y(2π)=2π, then 6y(π6)−8y(π4)6y\left(\frac{\pi}{6}\right) - 8y\left(\frac{\pi}{4}\right)6y(6π)−8y(4π) is equal to :AOption A. −3π-3\pi−3πBOption B. π\piπCOption C. 3π3\pi3πDOption D. −π-\pi−πCheckSkip · show solution