JEE Main 202430 Jan, Morning shiftMathematicsEasyDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation secx dy+{2(1−x)tanx+x(2−x)}dx=0\sec x \mathrm{~d} y+\{2(1-x) \tan x+x(2-x)\} \mathrm{d} x=0secx dy+{2(1−x)tanx+x(2−x)}dx=0 such that y(0)=2y(0)=2y(0)=2. Then y(2)y(2)y(2) is equal to:AOption A. 2{sin(2)+1}2\{\sin (2)+1\}2{sin(2)+1}BOption B. 2COption C. 1DOption D. 2{1−sin(2)}2\{1-\sin (2)\}2{1−sin(2)}CheckSkip · show solution
