JEE Main 202311 Apr, Evening shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation dydx+5x(x5+1)y=(x5+1)2x7,x>0\frac{d y}{d x}+\frac{5}{x\left(x^{5}+1\right)} y=\frac{\left(x^{5}+1\right)^{2}}{x^{7}}, x > 0dxdy+x(x5+1)5y=x7(x5+1)2,x>0. If y(1)=2y(1)=2y(1)=2, then y(2)y(2)y(2) is equal to :AOption A. 693128\frac{693}{128}128693BOption B. 697128\frac{697}{128}128697COption C. 637128\frac{637}{128}128637DOption D. 679128\frac{679}{128}128679CheckSkip · show solution
