JEE Main 202324 Jan, Evening shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2−3y2)dx+3xy dy=0,y(1)=1(x^2-3y^2)dx+3xy~dy=0,y(1)=1(x2−3y2)dx+3xy dy=0,y(1)=1. Then 6y2(e)6y^2(e)6y2(e) is equal toAOption A. 32e2\frac{3}{2}\mathrm{e}^223e2BOption B. 3e23\mathrm{e}^23e2COption C. e2\mathrm{e}^2e2DOption D. 2e22\mathrm{e}^22e2CheckSkip · show solution
