JEE Main 202324 Jan, Morning shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation x3dy+(xy−1)dx=0,x>0,y(12)=3−e{x^3}dy + (xy - 1)dx = 0,x > 0,y\left( {{1 \over 2}} \right) = 3 - \mathrm{e}x3dy+(xy−1)dx=0,x>0,y(21)=3−e. Then y (1) is equal toAOption A. 2 −-− eBOption B. 3COption C. 1DOption D. eCheckSkip · show solution
