JEE Main 20248 Apr, Evening shiftMathematicsMediumDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution curve of the differential equation secydy dx+2xsiny=x3cosy,y(1)=0\sec y \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x \sin y=x^3 \cos y, y(1)=0secy dxdy+2xsiny=x3cosy,y(1)=0. Then y(3)y(\sqrt{3})y(3) is equal to:AOption A. π6\frac{\pi}{6}6πBOption B. π12\frac{\pi}{12}12πCOption C. π3\frac{\pi}{3}3πDOption D. π4\frac{\pi}{4}4πCheckSkip · show solution
