JEE Main 20249 Apr, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let α,β\alpha, \betaα,β be the roots of the equation x2+22x−1=0x^2+2 \sqrt{2} x-1=0x2+22x−1=0. The quadratic equation, whose roots are α4+β4\alpha^4+\beta^4α4+β4 and 110(α6+β6)\frac{1}{10}(\alpha^6+\beta^6)101(α6+β6), is:AOption A. x2−180x+9506=0x^2-180 x+9506=0x2−180x+9506=0BOption B. x2−195x+9506=0x^2-195 x+9506=0x2−195x+9506=0COption C. x2−190x+9466=0x^2-190 x+9466=0x2−190x+9466=0DOption D. x2−195x+9466=0x^2-195 x+9466=0x2−195x+9466=0CheckSkip · show solution
