JEE Main 202313 Apr, Evening shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002Let α,β\alpha, \betaα,β be the roots of the equation x2−2x+2=0x^{2}-\sqrt{2} x+2=0x2−2x+2=0. Then α14+β14\alpha^{14}+\beta^{14}α14+β14 is equal toAOption A. −64-64−64BOption B. −642-64 \sqrt{2}−642COption C. −1282-128 \sqrt{2}−1282DOption D. −128-128−128CheckSkip · show solution
