Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, (γ₁)/(γ₂) is:

Thermodynamics: JEE Main 2023 Physics question

JEE Main 2023 · 24 Jan, Evening shift · Q7316

JEE Main 202324 Jan, Evening shiftPhysicsEasyThermodynamics163× since 2002

Let

\gamma_1

be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and

\gamma_2

be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio,

\frac{\gamma_1}{\gamma_2}

is :

JEE Main 2023 Thermodynamics Question with Solution (24 Jan Evening shift, Q7316) | JEE Arc

JEE Main 2023 · 24 Jan, Evening shift · Q7316

JEE Main 202324 Jan, Evening shiftPhysicsEasyThermodynamics163× since 2002

Let

\gamma_1

be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and

\gamma_2

be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio,

\frac{\gamma_1}{\gamma_2}

is :