Let P be the plane containing the straight line (x-3)/9=(y+4)/(-1)=(z-7)/(-5) and perpendicular to the plane containing the straight lines x/2=y/3=z/5 and x/3=y/7=z/8. If d is the distance of P from the point (2,-5,11), then d² is equal to:

Three Dimensional Geometry: JEE Main 2022 Mathematics question

JEE Main 2022 · 25 Jul, Morning shift · Q2449

JEE Main 202225 Jul, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let

\mathrm{P}

be the plane containing the straight line

\frac{x-3}{9}=\frac{y+4}{-1}=\frac{z-7}{-5}

and perpendicular to the plane containing the straight lines

\frac{x}{2}=\frac{y}{3}=\frac{z}{5}

and

\frac{x}{3}=\frac{y}{7}=\frac{z}{8}

. If

\mathrm{d}

is the distance of

\mathrm{P}

from the point

(2,-5,11)

, then

\mathrm{d}^{2}

is equal to :