Let a n be the n^(th) term of the series 5+8+14+23+35+50+ and S n =Σ k=1 ⁿ a k. Then S₃₀-a₄₀ is equal to:

Sequence and Series: JEE Main 2023 Mathematics question

JEE Main 2023 · 8 Apr, Evening shift · Q5344

JEE Main 20238 Apr, Evening shiftMathematicsMediumSequence and Series179× since 2002

Let

\mathrm{a}_{\mathrm{n}}

be the

\mathrm{n}^{\text {th }}

term of the series

5+8+14+23+35+50+\ldots

and

\mathrm{S}_{\mathrm{n}}=\sum_\limits{k=1}^{n} a_{k}

. Then

\mathrm{S}_{30}-a_{40}

is equal to :

JEE Main 2023 · 8 Apr, Evening shift · Q5344

JEE Main 20238 Apr, Evening shiftMathematicsMediumSequence and Series179× since 2002

Let

\mathrm{a}_{\mathrm{n}}

be the

\mathrm{n}^{\text {th }}

term of the series

5+8+14+23+35+50+\ldots

and

\mathrm{S}_{\mathrm{n}}=\sum_\limits{k=1}^{n} a_{k}

. Then

\mathrm{S}_{30}-a_{40}

is equal to :