JEE Main 2003Annual, Paper 1PhysicsMediumRotational Motion140× since 2002Let F→\overrightarrow FF be the force acting on a particle having position vector r→,\overrightarrow r ,r, and τ→\overrightarrow \tauτ be the torque of this force about the origin. ThenAOption A. r.→τ→=0 \overrightarrow {r.} \overrightarrow \tau = 0\,\,r.τ=0 and F.→τ→≠0 \overrightarrow {F.} \overrightarrow \tau \ne 0\,\,F.τ=0BOption B. r.→τ⃗≠0 \overrightarrow {r.} \vec \tau \ne 0{\mkern 1mu} {\mkern 1mu}r.τ=0 and F.→τ→=0 \overrightarrow {F.} \overrightarrow \tau = 0\,\,F.τ=0COption C. r.→τ⃗≠0 \overrightarrow {r.} \vec \tau \ne 0{\mkern 1mu}r.τ=0 and F.→τ→≠0\overrightarrow {F.} \overrightarrow \tau \ne 0F.τ=0DOption D. r.→τ⃗=0 \overrightarrow {r.} \vec \tau = 0{\mkern 1mu}r.τ=0 and F.→τ→=0 \overrightarrow {F.} \overrightarrow \tau = 0\,\,F.τ=0CheckSkip · show solution
