JEE Main 20249 Apr, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002Let f(x)=ax3+bx2+cx+41f(x)=a x^3+b x^2+c x+41f(x)=ax3+bx2+cx+41 be such that f(1)=40,f′(1)=2f(1)=40, f^{\prime}(1)=2f(1)=40,f′(1)=2 and f′′(1)=4f^{\prime \prime}(1)=4f′′(1)=4. Then a2+b2+c2a^2+b^2+c^2a2+b2+c2 is equal to:AOption A. 54BOption B. 51COption C. 73DOption D. 62CheckSkip · show solution
