Let 9=x₁ < x₂ < < x₇ be in an A.P. with common difference d. If the standard deviation of x₁, x₂..., x₇ is 4 and the mean is x, then x+x₆ is equal to:

Statistics and Probability: JEE Main 2023 Mathematics question

JEE Main 2023 · 1 Feb, Evening shift · Q5476

JEE Main 20231 Feb, Evening shiftMathematicsMediumStatistics and Probability258× since 2002

Let

9=x_{1} < x_{2} < \ldots < x_{7}

be in an A.P. with common difference d. If the standard deviation of

x_{1}, x_{2}..., x_{7}

is 4 and the mean is

\bar{x}

, then

\bar{x}+x_{6}

is equal to :