JEE Main 202331 Jan, Evening shiftMathematicsMediumSequence and Series179× since 2002Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1,a2,a3,… be an A.P. If a7=3a_7=3a7=3, the product a1a4a_1 a_4a1a4 is minimum and the sum of its first nnn terms is zero, then n!−4an(n+2)n !-4 a_{n(n+2)}n!−4an(n+2) is equal to :AOption A. 24BOption B. 3814\frac{381}{4}4381COption C. 9DOption D. 334\frac{33}{4}433CheckSkip · show solution