JEE Main 20246 Apr, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002Let f(x)=17−sin5xf(x)=\frac{1}{7-\sin 5 x}f(x)=7−sin5x1 be a function defined on R\mathbf{R}R. Then the range of the function f(x)f(x)f(x) is equal to :AOption A. [18,15]\left[\frac{1}{8}, \frac{1}{5}\right][81,51]BOption B. [17,16]\left[\frac{1}{7}, \frac{1}{6}\right][71,61]COption C. [17,15]\left[\frac{1}{7}, \frac{1}{5}\right][71,51]DOption D. [18,16]\left[\frac{1}{8}, \frac{1}{6}\right][81,61]CheckSkip · show solution
