Let f:(1,∞) be a function defined as f(x)=(x-1)/(x+1). Let fⁱ⁺¹(x)=f(fⁱ(x)), i=1,2,,25, where f¹(x)=f(x). If g(x)+f²⁶(x)=0, x (1,∞), then the area of the region bounded by the curves y=g(x), 2y=2x-3, y=0 and x=4 is:

Integral Calculus: JEE Main 2026 Mathematics question

JEE Main 2026 · 8 Apr, Evening shift · Q18

JEE Main 20268 Apr, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

Let

f:(1,\infty)\to\mathbb{R}

be a function defined as

f(x)=\frac{x-1}{x+1}

. Let

f^{i+1}(x)=f\left(f^i(x)\right)

i=1,2,\ldots,25

, where

f^1(x)=f(x)

. If

g(x)+f^{26}(x)=0

x\in(1,\infty)

, then the area of the region bounded by the curves

y=g(x)

2y=2x-3

y=0

and

x=4

is :

JEE Main 2026 Integral Calculus Question with Solution (8 Apr Evening shift, Q18) | JEE Arc