JEE Main 20231 Feb, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002Let f:R−0,1→Rf:\mathbb{R}-{0,1}\to \mathbb{R}f:R−0,1→R be a function such that f(x)+f(11−x)=1+xf(x)+f\left(\frac{1}{1-x}\right)=1+xf(x)+f(1−x1)=1+x. Then f(2)f(2)f(2) is equal toAOption A. 94\frac{9}{4}49BOption B. 74\frac{7}{4}47COption C. 73\frac{7}{3}37DOption D. 92\frac{9}{2}29CheckSkip · show solution