JEE Main 202624 Jan, Evening shiftMathematicsEasyDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be a differentiable function in the interval (0,∞)(0,\infty)(0,∞) such that y(1)=2y(1)=2y(1)=2, and limt→x(t2y(x)−x2y(t)x−t)=3\lim_{t\to x}\left(\frac{t^2y(x)-x^2y(t)}{x-t}\right)=3limt→x(x−tt2y(x)−x2y(t))=3 for each x>0x>0x>0. Then 2y(2)2y(2)2y(2) is equal toAOption A. 18BOption B. 27COption C. 23DOption D. 12CheckSkip · show solution