JEE Main 20238 Apr, Morning shiftMathematicsMediumSequence and Series179× since 2002Let SK=1+2+…+KKS_{K}=\frac{1+2+\ldots+K}{K}SK=K1+2+…+K and \sum_\limits{j=1}^{n} S_{j}^{2}=\frac{n}{A}\left(B n^{2}+C n+D\right), where A,B,C,D∈NA, B, C, D \in \mathbb{N}A,B,C,D∈N and AAA has least value. ThenAOption A. A+B+C+DA+B+C+DA+B+C+D is divisible by 5BOption B. A+C+DA+C+DA+C+D is not divisible by BBBCOption C. A+B=5(D−C)A+B=5(D-C)A+B=5(D−C)DOption D. A+BA+BA+B is divisible by D\mathrm{D}DCheckSkip · show solution