JEE Main 202131 Aug, Morning shiftMathematicsHardVector Algebra184× since 2002Let a→\overrightarrow aa and b→\overrightarrow bb be two vectors such that ∣2a→+3b→∣=∣3a→+b→∣\left| {2\overrightarrow a + 3\overrightarrow b } \right| = \left| {3\overrightarrow a + \overrightarrow b } \right|2a+3b=3a+b and the angle between a→\overrightarrow aa and b→\overrightarrow bb is 60∘^\circ∘. If 18a→{1 \over 8}\overrightarrow a81a is a unit vector, then ∣b→∣\left| {\overrightarrow b } \right|b is equal to :AOption A. 4BOption B. 6COption C. 5DOption D. 8CheckSkip · show solution