JEE Main 202324 Jan, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let p,q∈R\mathrm{p,q\in\mathbb{R}}p,q∈R and (1−3i)200=2199(p+iq),i=−1{\left( {1 - \sqrt 3 i} \right)^{200}} = {2^{199}}(p + iq),i = \sqrt { - 1}(1−3i)200=2199(p+iq),i=−1 then p+q+q2\mathrm{p+q+q^2}p+q+q2 and p−q+q2\mathrm{p-q+q^2}p−q+q2 are roots of the equation.AOption A. x2+4x−1=0{x^2} + 4x - 1 = 0x2+4x−1=0BOption B. x2−4x+1=0{x^2} - 4x + 1 = 0x2−4x+1=0COption C. x2+4x+1=0{x^2} + 4x + 1 = 0x2+4x+1=0DOption D. x2−4x−1=0{x^2} - 4x - 1 = 0x2−4x−1=0CheckSkip · show solution
