JEE Main 202427 Jan, Evening shiftMathematicsEasyPermutations and Combinations98× since 2002Let α=(4!)!(4!)3!\alpha=\frac{(4 !) !}{(4 !)^{3 !}}α=(4!)3!(4!)! and β=(5!)!(5!)4!\beta=\frac{(5 !) !}{(5 !)^{4 !}}β=(5!)4!(5!)!. Then :AOption A. α∈N\alpha \in \mathbf{N}α∈N and β∈N\beta \in \mathbf{N}β∈NBOption B. α∈N\alpha \in \mathbf{N}α∈N and β∉N\beta \notin \mathbf{N}β∈/NCOption C. α∉N\alpha \notin \mathbf{N}α∈/N and β∈N\beta \in \mathbf{N}β∈NDOption D. α∉N\alpha \notin \mathbf{N}α∈/N and β∉N\beta \notin \mathbf{N}β∈/NCheckSkip · show solution
