JEE Main 202624 Jan, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002Let A(1,0)A(1, 0)A(1,0), B(2,−1)B(2, -1)B(2,−1) and C(73,43)C\left(\frac{7}{3}, \frac{4}{3}\right)C(37,34) be three points. If the equation of the bisector of the angle ABC is αx+βy=5\alpha x + \beta y = 5αx+βy=5, then the value of α2+β2\alpha^2 + \beta^2α2+β2 isAOption A. 131313BOption B. 888COption C. 101010DOption D. 555CheckSkip · show solution