JEE Main 202430 Jan, Evening shiftMathematicsMediumVector Algebra184× since 2002Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors such that ∣b⃗∣=1|\vec{b}|=1∣b∣=1 and ∣b⃗×a⃗∣=2|\vec{b} \times \vec{a}|=2∣b×a∣=2. Then ∣(b⃗×a⃗)−b⃗∣2|(\vec{b} \times \vec{a})-\vec{b}|^2∣(b×a)−b∣2 is equal toAOption A. 1BOption B. 3COption C. 5DOption D. 4CheckSkip · show solution