JEE Main 202311 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let fff and ggg be two functions defined by f(x)={x+1,x<0∣x−1∣,x≥0f(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\ |x-1|, & x \geq 0\end{array}\right.f(x)={x+1,∣x−1∣,x<0x≥0 and g(x)={x+1,x<01,x≥0\mathrm{g}(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\ 1, & x \geq 0\end{array}\right.g(x)={x+1,1,x<0x≥0 Then (g∘f)(x)(g \circ f)(x)(g∘f)(x) is :AOption A. continuous everywhere but not differentiable at x=1x=1x=1BOption B. differentiable everywhereCOption C. not continuous at x=−1x=-1x=−1DOption D. continuous everywhere but not differentiable exactly at one pointCheckSkip · show solution
