Let α and β be the roots of the equation p x²+q x-r=0, where p ≠ 0. If p, q and r be the consecutive terms of a non constant G.P. and 1/(α)+1/(β)=3/4, then the value of (α-β)² is:

Complex Numbers and Quadratic Equations: JEE Main 2024 Mathematics question

JEE Main 2024 · 1 Feb, Evening shift · Q5166

JEE Main 20241 Feb, Evening shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

Let

\alpha

and

\beta

be the roots of the equation

p x^2+q x-r=0

, where

p \neq 0

. If

p, q

and

r

be the consecutive terms of a non constant G.P. and

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{3}{4}

, then the value of

(\alpha-\beta)^2

is :