JEE Main 2014Session, Shift 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let α\alphaα and β\betaβ be the roots of equation px2+qx+r=0,p{x^2} + qx + r = 0,px2+qx+r=0, p≠0.p \ne 0.p=0. If p, q, rp,\,q,\,rp,q,r in A.P. and 1α+1β=4,{1 \over \alpha } + {1 \over \beta } = 4,α1+β1=4, then the value of ∣α−β∣\left| {\alpha - \beta } \right|∣α−β∣ is :AOption A. 349{{\sqrt {34} } \over 9}934BOption B. 2139{{2\sqrt 13 } \over 9}9213COption C. 619{{\sqrt {61} } \over 9}961DOption D. 2179{{2\sqrt 17 } \over 9}9217CheckSkip · show solution
