JEE Main 202226 Jun, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let A={z∈C:∣z+1z−1∣<1}A = \left\{ {z \in C:\left| {{{z + 1} \over {z - 1}}} \right| < 1} \right\}A={z∈C:z−1z+1<1} and B={z∈C:arg(z−1z+1)=2π3}B = \left\{ {z \in C:\arg \left( {{{z - 1} \over {z + 1}}} \right) = {{2\pi } \over 3}} \right\}B={z∈C:arg(z+1z−1)=32π}. Then A ∩\cap∩ B is :AOption A. a portion of a circle centred at (0,−13)\left( {0, - {1 \over {\sqrt 3 }}} \right)(0,−31) that lies in the second and third quadrants onlyBOption B. a portion of a circle centred at (0,−13)\left( {0, - {1 \over {\sqrt 3 }}} \right)(0,−31) that lies in the second quadrant onlyCOption C. an emptyDOption D. a portion of a circle of radius 23{2 \over {\sqrt 3 }}32 that lies in the third quadrant onlyCheckSkip · show solution
